Anonymous at Wed, 6 Mar 2024 20:21:04 UTC No. 16060308
>>16060298
thought it was some cool pattern that takes some thinking to figure out, its just f(a,b) = a*b + a
f(8,11) = 8*11 + 8 = 96
Anonymous at Wed, 6 Mar 2024 20:25:28 UTC No. 16060312
>>16060298
new math just dropped
Anonymous at Wed, 6 Mar 2024 20:30:58 UTC No. 16060314
>1+4=5
yes
>2+5=12
wrong
>3+6=21
wrong
>8+11=?
19
and nothing else you niggers
dont @ me
Anonymous at Wed, 6 Mar 2024 20:42:28 UTC No. 16060330
>>16060308
It can also be
f(a,b) = a*(4+a)
or an infinite amount of other formulas.
Anonymous at Wed, 6 Mar 2024 20:43:55 UTC No. 16060334
>>16060330
but my function is obviously the one that the creator of that image meant.
Anonymous at Wed, 6 Mar 2024 20:48:52 UTC No. 16060343
>>16060330
>or an infinite amount of other formulas.
Proof?
Anonymous at Wed, 6 Mar 2024 21:03:05 UTC No. 16060359
>>16060343
Development of this proof is left as an exercise for the reader. It should be developed alongside the proof that you're not a retarded baiter.
Anonymous at Wed, 6 Mar 2024 21:12:07 UTC No. 16060369
Forty?
Anonymous at Wed, 6 Mar 2024 21:30:55 UTC No. 16060379
>>16060298
1 + 4 = 5
2 + 5 = 7 + 5 = 12
3 + 6 = 9 + 12 = 21
8 + 11 = 19 + 21 = 40
Anonymous at Wed, 6 Mar 2024 22:22:30 UTC No. 16060445
>>16060298
19 is a crazy number. Just crazy.
Anonymous at Wed, 6 Mar 2024 23:23:06 UTC No. 16060527
>>16060298
a + b is actually a(b+1)
1 * (4 + 1) = 5
2 * (5+1) = 12
3 * (6 + 1) = 21
8 * (11+1) = 96
you can't refute this
Anonymous at Wed, 6 Mar 2024 23:54:40 UTC No. 16060568
>>16060298
[math]x_{1}+x_{4}-x_{5}=0[/math]
[math]x_{2}+x_{5}-x_{0}=0[/math]
[math]x_{3}+x_{6}-x_{7}=0[/math]
[math]x_{8}+x_{9}=?[/math]
>ten variables
>three equations
>the problem asks about an expresion that is clearly "linearly independent" from the previous three
El Arcón at Wed, 6 Mar 2024 23:57:32 UTC No. 16060571
>>16060568
yeah
Anonymous at Thu, 7 Mar 2024 00:05:31 UTC No. 16060585
>>16060298
40
5+5+2=12
12+3+6=21
21+8+11=40
Anonymous at Thu, 7 Mar 2024 10:56:41 UTC No. 16061200
52
Anonymous at Thu, 7 Mar 2024 12:10:59 UTC No. 16061254
>>16060298
2 + 5 is 7
Anonymous at Thu, 7 Mar 2024 13:09:09 UTC No. 16061291
Anonymous at Thu, 7 Mar 2024 13:14:32 UTC No. 16061302
>>16060298
201
Anonymous at Thu, 7 Mar 2024 19:31:58 UTC No. 16061692
Anonymous at Thu, 7 Mar 2024 21:16:30 UTC No. 16061828
>>16060298
are you all retarded? its literally the result + the previous result
8+11 = 32
Anonymous at Thu, 7 Mar 2024 21:29:28 UTC No. 16061850
>>16060298
1 + 4(x1) = 5
2 + 5 (x2) = 12
3 + 6 (x3) = 21
4 + 7 (x4) = 32
5 + 8 (x5) = 45
6 + 9 (x6) = 60
7 + 10 (x7) = 77
8 + 11 (x8) = 96
yuo = fagot
https://pastebin.com/kcPLQwGh
Anonymous at Thu, 7 Mar 2024 21:35:39 UTC No. 16061861
>>16060298
2+5 is 7
Anonymous at Thu, 7 Mar 2024 22:00:23 UTC No. 16061897
Anonymous at Fri, 8 Mar 2024 16:28:56 UTC No. 16062988
>>16060308
why does the operator plus signify simply an addition in your made up wacky function but when I look at the question it is something else entirely, if you use plus again in your function then it should be recursive, this is not fair, it doesn't make any sense
Anonymous at Fri, 8 Mar 2024 20:48:40 UTC No. 16063501
>>16062988
You should use a donut operator between those, yes, but it's intended as a fun puzzle and if regular people see a placeholder operator they will go https://www.youtube.com/watch?v=xVW
On the other hand, it's profitable if math autists also realize the addition symbol is indeed arbitrary and does not inherently denote addition. This is trivially true as math symbols are already overloaded and denote quite different things within different subdisciplines.
Anonymous at Fri, 8 Mar 2024 21:19:06 UTC No. 16063572
>>16063501
Alternatively those are not numbers, those are niggbers, and to add two niggbers you do ab + a.
Anonymous at Fri, 8 Mar 2024 21:22:19 UTC No. 16063579
>>16060585
Was thinking the same
Anonymous at Fri, 8 Mar 2024 22:33:07 UTC No. 16063715
>>16060298
1+ 4 = 5 (base 6)
2 + 5 = 12 (base 5)
3 + 6 = 21 (base 4)
8 + 11 = undefined (base -1 is undefined)
9 + 12 = 10101 (base -2)