๐งต Untitled Thread
Anonymous at Sun, 17 Mar 2024 14:29:41 UTC No. 16083065
i wrote a quick program to calculate the riemann zeta function in c# is this correct?
static double NthRoot(double A, double N)
{
double epsilon = 0.00001d;//
double n = N;
double x = A / n;
while (Math.Abs(A-Math.Pow(x,N)) > epsilon)
{
x = (1.0d/n) * ((n-1)*x + (A/(Math.Pow(x, N-1))));
}
return x;
}
public static Complex calculatezeta(double real, double imaginary, int depth)
{
Complex result = 0;
for (int i = 1; i < depth; i++)
{
double ddepth = (double)depth;
result += 1.0/
((Math.Cos(real*imaginary*Math.Log(
Complex.ImaginaryOne * Math.Sin(real*imaginary*Math.Log((d
NthRoot(Math.Pow((double)i,2), real*(1.0/2.0))
);
}
return result;
}
static void Main(string[] args)
{
Console.WriteLine(calculatezeta(1.0
Console.WriteLine(calculatezeta(25.
Console.WriteLine(new System.Numerics.Complex(calculateze
Console.WriteLine(calculatezeta(1.5
Console.WriteLine(calculatezeta(25.
Console.WriteLine(new System.Numerics.Complex(calculateze
๐๏ธ Anonymous at Mon, 18 Mar 2024 18:31:55 UTC No. 16085096
>>16083065
DOODOOSHIT
Anonymous at Mon, 18 Mar 2024 20:53:56 UTC No. 16085387
>>16083065
ok but for what purpose
Anonymous at Mon, 18 Mar 2024 23:04:36 UTC No. 16085641
>>16085387
studying the question.. im curiious about it
>>16085101
oh hey can you post your proof/falsification again i want to read it.
Anonymous at Mon, 18 Mar 2024 23:12:26 UTC No. 16085653
>>16083065
math is not real
Anonymous at Tue, 19 Mar 2024 01:08:28 UTC No. 16085801
>>16085641
Ok but if you were to try to shift the zeroes to the right or left from the axis like you would with a polynomial by dividibg the x by ab altered real part it wouldnt work because in the exponentiation the w variable is independent from the real part at the end which speaks against false meaning you couldnt shift it to the right or left using the real input
Anonymous at Tue, 19 Mar 2024 01:13:47 UTC No. 16085807
>>16085801
Meaning the square root in the exponentiation is correlated with the R however independent of it which in turn algebraically makes r dependent on the squareroot in the exponentiation which term converges to infinity this term would converge faster with infinity than you could alter the finite term R
Anonymous at Tue, 19 Mar 2024 01:17:04 UTC No. 16085810
>>16085807
Because of this you couldnt alter the time axis which is N like you would alter the x axis in a polynomial to shift the zeroes to the right or left
Anonymous at Tue, 19 Mar 2024 01:22:43 UTC No. 16085813
>>16083065
keep in mind the only way the riemann hypothesis couild be true is if it was analogous to a polynomial but it is not polynomial form, so it doesnt have the derivative of a polynomial to enable a zero being on non 1/2
Anonymous at Tue, 19 Mar 2024 01:47:09 UTC No. 16085828
>>16085813
shit that one was wrong the R is also on the square root of the exponentiation
Anonymous at Tue, 19 Mar 2024 01:50:59 UTC No. 16085834
>>16085828
but the root as w approaches infinite should be the same for any radix though
Anonymous at Tue, 19 Mar 2024 01:52:49 UTC No. 16085835
>>16083065
>is this correct?
Output a .svg text file and open it with some browser.