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๐Ÿงต Fun trivial proof of at least one prime

Anonymous No. 16085822

The arithmetic progression of the form 3n+1 contains at least one prime.
Assume it doesn't, then for any natural a, b, (3a+2)(3b+2)=3c+1 so that there is a bijection between naturals c and (a, b).

But notice that (3a+2)(3b+2)=((3a+1)+1)((3b+1+1))=((3x+2)(3y+2)+1)((3z+2)(3w+2)+1)

Notice something weird?
You guessed it if you look at mod 3, the remainder (number not factored by x or y or z or w) tends to a very big number the more such "nesting" is performed on the form (3n+2).

Brilliant! In fact this proof works for every prime p and 0 < q <p for the progression pn+q.

I won't tell you the details of course because I don't want to spoil anything (hint: just decompose a progression into corresponding multiples of progressions(

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Anonymous No. 16085829

Implicitly, [math]\alpha(n)=3n+1[/math] is and endomorphism on the natural numbers and so is [math]\phi(a, b)=(3a+2)(3b+2)[/math] so that the composition [math]\alpha^{-1}\circ\phi[/math] is a bijection.
Then there's nesting [math]\phi=(\phi+1)(\phi+1)[/math]
And finally there's a contradiction since there is a very big margin in the image of [math]\alpha^{-1}\circ\phi[/math] once nesting is applied.
Hence there is at least one prime number.

Tadaa..

Anonymous No. 16085833

>>16085829
Uhhh I meant a surjection

Anonymous No. 16085899

>Numbers that are +1 or -1 an even number have a chance of being prime.
Holy shit

Anonymous No. 16086346

>>16085899
If you are so smart why don't you show me there is a prime number in any good irreducible polynomial?

Right, you can't, because you are a retarded nigger who doesn't understands the subjwct

bodhi No. 16086360

>>16086346
Cope, I have achieved more than you

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Anonymous No. 16086375

>>16086360
I don't even know you, I messaged the other dude.

You are just another uneducated schizo on this board who misreads and bullies people with a fictitious sense of superiority.

Know your place

bodhi No. 16086378

>>16086375
post your thesis first, then we can talk

Anonymous No. 16086384

Wait til this nigga learns about 6n+1 and stops checking even numbers for primes

Anonymous No. 16086455

>>16086384
You are a worthless undergrad who thinks I will give him a free proof of at least one prime in 6n+1

Go back to doing your homework retarded worthless talentless children

>>16086378
You don't have a thesis because you are this retarded /sci/ schizophrenia who keeps making up shit here, either way I don't share my personal info to some retarded strangers here so you'll have to contact me personally

Barkon No. 16086600

>>16086455
Mathematician here. Seems to me you've lost. Better stop posting before you embarrass yourself further

Anonymous No. 16086606

>>16086455
>at least one prime in 6n+1
Set n=1

Garrote No. 16086620

wtf 7 is prime

Anonymous No. 16086623

>>16086606
op btfo

Anonymous No. 16086747

>>16085822
7

Anonymous No. 16086759

>>16085822
>proof by contradiction
You haven't solved the problem

Anonymous No. 16087710

>>16085822
Damn so 7 is a prime

Anonymous No. 16087805

>>16085822
let me clean up your mess so you can see the mistakes
>assume 3c+1 is not prime
>then for some a,b we can nontrivially factor either 3c+1 = (3a+1)(3b+1) or 3c+1=(3a+2)(3b+2)
>either way, a,b are each smaller than c
>now assume 3a+1, 3b+1 are not prime and repeat
>continue until we reach a=b=0
>now our last โ€œcโ€ must equal 4
Iโ€™m not sure what this says about the initial number

bodhi No. 16089126

OP sure got BTFO'd hard