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πŸ—‘οΈ 🧡 Untitled Thread

Anonymous No. 16107325

Let [math]P(x)[/math] be a polynomial with solution [math]\sqrt[3]{a} +\sqrt[3]{b}[/math] and [math]a,b \in Z[/math].

The general solution is [math]x^9-3(a+b)x^6-[/math] [-------------] [math]x^3-(a+b)^3[/math].

Fill in the missing part.

Anonymous No. 16107352

homework thread

Anonymous No. 16107355

>>16107352
Nah, I made this up. It’s too retarded to be homework.

Anonymous No. 16107460

>>16107325
[math]3(a^2-7ba+b^2)x^3[/math]

Anonymous No. 16107465

You have just landed in the rabbit hole of Sylvester Matrices, Resultants, and weird algebraic number tricks.

Anonymous No. 16107922

Also got [math]P(x) = x^9 - 3(a+b)x^6 + 3(a^2-7ab+b^2)x^3 - (a+b)^3[/math].
I just multiplied out [math]\prod_{m=0}^2 \prod_{n=0}^2 (x - \omega^m A - \omega^n B)[/math] where [math]\omega = e^{2\pi i/3}[/math].
Tedious but simple.

Anonymous No. 16107924

>>16107922
And where [math]A = \sqrt[3]{a}[/math], [math]B = \sqrt[3]{b}[/math].