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๐Ÿ—‘๏ธ ๐Ÿงต Untitled Thread

Anonymous No. 16145935

Can you quickly check if I transformed that correctly?
My friend is saying "S can't be negative" and that's what you end up with if you plug in the data.

Anonymous No. 16145940

homework thread

Anonymous No. 16145946

>>16145940
it's not homework, but I understand your objection. If I knew anyone else who knows photochemistry I would ask.

Anonymous No. 16146085

Please, make an exception for me, please.

Anonymous No. 16146099

>>16145935
Whether S is negative depends on the parameters. You could rewrite it to remove the minus sign but that wouldn't change the answer.

Anonymous No. 16146107

>>16145935
Your algebra is correct.
you can distribute the negative into the bottom half of the fraction if you want to please your friend

Anonymous No. 16146118

>>16146107
>>16146099
I just realized ln of a fraction returns z negative number so it evens out. Sorry for a retarded question, then...

Anonymous No. 16146140

>>16146118
If it was a retarded question then you would have known how to do it out the womb. Humans do not know how to do this out the womb, thus it is not a retarded question

Anonymous No. 16146178

CAN I PLEASE HAVE ATTEBTION RIGHT NOW

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Anonymous No. 16146281

>>16145935
>>16145946
Is this supposed to be photoinactivation at a specific light intensity over time or something?
If the photoinactivation is negative, that means either that photosynthetic repair is happening, or NPQ is decreasing.
So positive S "oh no the plant is under light stress".
And negative S "oh look the plant is recovering".

Did I nail it?