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Anonymous at Wed, 15 May 2024 06:38:23 UTC No. 16176743
I'm trying to figure out how much Voltage I would need to attach to a wire to burn through a very thin piece of plastic that's hanging from said wire.
The plastic wire melts at 90°C. Anyway, the way I would do it is:
Solve for Q where m is the mass of the wire, c is the specific heat capacity of the plastic and deltaT is the change in temperature needed.
Q=mcΔT
Then apply Joules Law and Solve for I
Q = I2 * R * t
Once you got your Current you can infer the Voltage.
Thoughts? Pic unrelated
Anonymous at Wed, 15 May 2024 06:53:01 UTC No. 16176750
>>16176743
Your wire has to get up to the right temperature, the specific heat of the plastic is irrelevant. Nobody cares about specific heat of solder, they just get the soldering iron to the right temperature.
Anonymous at Wed, 15 May 2024 06:56:45 UTC No. 16176757
there is an obvious time dependence. The more voltage, the less time it takes. And vice versa.
Also, your model does not account heat dissipation to the air surrounding it.
Anonymous at Wed, 15 May 2024 07:04:15 UTC No. 16176764
>>16176750
I guess that's true
>>16176757
Oh shit, you're right. I'll think about it some more.
Anonymous at Wed, 15 May 2024 07:21:17 UTC No. 16176779
>>16176743
What are you planning to do? This whole post sounds sus af.
Anonymous at Wed, 15 May 2024 07:45:38 UTC No. 16176788
>>16176779
Dont worry about it.
Anonymous at Wed, 15 May 2024 10:01:13 UTC No. 16176878
>>16176743
The correct apprach is to figure out what the convection/conduction heat flux losses are in the wire at your target temperature and then figure out how much ohmic power deposition you need to balance it at steady state.