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Anonymous at Thu, 16 May 2024 10:43:43 UTC No. 16178196
Shouldn't gases with only three translational degrees of freedom have a higher diffusion coefficient than a gas with additional rotational and vibrational degrees of freedoms, because they don't have to distribute their thermal energy towards these rotational and vibrational degrees of freedoms, which don't contribute to the diffusion coefficient?
Anonymous at Thu, 16 May 2024 13:53:37 UTC No. 16178390
>>16178196
Temperature is defined using only the translational kinetic energy. For a given temperature, a more complex molecule will have the same translational energy as a monatomic gas, but more total energy. That's why specific heat in an ideal gas is proprtional to the number of degrees of freedom.
Anonymous at Thu, 16 May 2024 21:47:30 UTC No. 16178971
>>16178390
I know that, but what I am wondering is why molecules with higher degrees of freedom have a higher translational kinetic energy at the same temperature than one with lesser degrees of freedom?
Anonymous at Fri, 17 May 2024 09:10:51 UTC No. 16179564
>>16178971
idk
Anonymous at Fri, 17 May 2024 10:58:38 UTC No. 16179656
>>16178971
You obviously don't know that.
molecules with higher degrees of freedom have THE SAME translational kinetic energy at the same temperature as ones with lesser degrees of freedom.
Anonymous at Fri, 17 May 2024 13:50:21 UTC No. 16179864
>>16178196
>vibrational
that's a translation anon...
>rotational
name a gas that can't rotate
Anonymous at Fri, 17 May 2024 13:55:15 UTC No. 16179873
>>16179864
argon
Anonymous at Sat, 18 May 2024 05:06:47 UTC No. 16181019
>>16178196
No you stupid jew back to preschool