🧵 Dividing temperatures
Anonymous at Tue, 28 May 2024 16:47:21 UTC No. 16197870
I want to divide a temperature range (18.0 C to 24.0 C) into three equal parts. That should be straightforward enough, 24 - 18 = 6, 6/3 = 2. So each third is 2 degrees. But the problem is how to demarcate each category. Does the first third start at 18 and end at 20? Then the second third starts at 20 and ends at 22? But the problem is, which third does 20 belong to? The first or the 2nd?
Anonymous at Tue, 28 May 2024 16:52:32 UTC No. 16197880
>>16197870
depending on how many decimal places a thermostat goes to i would do
18 - 19.9
20 - 21.9
22 - 23.9 or 24.0
if you are calculating things like thermal entropy you need a better solution
Anonymous at Wed, 29 May 2024 01:53:27 UTC No. 16198520
>>16197870
Bump.
Anonymous at Wed, 29 May 2024 01:54:43 UTC No. 16198522
homework thread
Anonymous at Wed, 29 May 2024 02:27:23 UTC No. 16198552
>>16197870
Just relabel your units of temperature measurement to [math]\hbar / k[/math] where [math]\hbar[/math] is the reduced Planck's constant and [math]k[/math] is Boltzmann's constant. Then, since your thermostat is a classical device, the energy-time uncertainty principle ensures that it's useless to worry about its behavior at the exact midpoint, since there won't be enough time for the device to display such a reading anyway.