🧵 Volts & Amps
The light at Sun, 23 Jun 2024 02:46:21 UTC No. 16248649
The light at Sun, 23 Jun 2024 02:49:37 UTC No. 16248652
>>16248649
So I have a question which maybe simple to some, but I’ve got a basic understanding of Volts and Amps
My question is there a difference? I think is but curious.
Say I have a bulb that is 2.4volts and 0.9amps running on 2 d cell batteries of 1.2 volts each
Then I have the same batteries running on a bulb of 2.2volts and 0.5amps.
From my basic understanding that 2.2volt build will last longer on the batteries but not produce as much watts?
Anonymous at Sun, 23 Jun 2024 03:11:57 UTC No. 16248681
>>16248649
Not how that works. Batteries determine voltage applied to the circuit, not the bulb.
The light at Sun, 23 Jun 2024 03:29:38 UTC No. 16248693
>>16248681
Okay so the colts that the batteries put out actually determine the overall volts going through the bulb?
So if the batteries are 1.2 volt each they will equal to 2.4 volts with 2 batteries regardless?
Okay so, why do certain bulbs have different volts and amp ratings on them?
Anonymous at Sun, 23 Jun 2024 06:15:00 UTC No. 16248837
>>16248693
yes, the 2.2V|0.5A bulb will shine longer than the 2.4V|0.9A bulb because at that working point(around 2.3V) it offers a higher resistance (2.2V/0.5A) than the other bulb(2.4V/0.9A). the current drawn from the battery will be less. batteries are not ideal voltage sources though. they have to be modelled using an internal resistance that increases over the lifetime of the battery. should be fine for your case with d cells though.
voltage is the potential (difference) and determines how much current *could* flow. current is the actual amount of stuff (charges) that flows. the resistance of a load then is the deciding factor(together with the battery internal resistance) how much current the voltage source(battery) is allowed to provide. compared to other loads bulbs don't have a fixed resistance. it strongly depends on the temperature which is in turn pretty much determined by its current wattage(voltage times current). voltage and wattage markings allow to calculate its wattage and resistance(voltage divided by current) at that working point.
Anonymous at Sun, 23 Jun 2024 06:18:08 UTC No. 16248844
>>16248837
*current markings
Anonymous at Sun, 23 Jun 2024 07:04:17 UTC No. 16248875
>>16248837
Is that AI?
Anonymous at Sun, 23 Jun 2024 07:52:11 UTC No. 16248923
Anonymous at Sun, 23 Jun 2024 07:59:16 UTC No. 16248932
>>16248875
>Is that AI?
if it's correct, what does it matter?
The light at Sun, 23 Jun 2024 12:29:52 UTC No. 16249091
>>16248837
Okay, I kinda had that feeling basically the lower volt and amp bulb basically allows lesser flow so the battery last longer!
>>16248923
That is actually a neat drawing. I’ve learned that ohms law is basically the natural resistance that occurs
Anonymous at Sun, 23 Jun 2024 13:38:02 UTC No. 16249140
>>16248875
AI uses proper capitalisation