Anonymous at Fri, 28 Jun 2024 15:01:56 UTC No. 16258200

>>16258199
cont'd

Anonymous at Fri, 28 Jun 2024 15:04:31 UTC No. 16258202

>>16258199
>>16258200
Hold up, just going to bang that into MATLAB and let it do it for me

Anonymous at Fri, 28 Jun 2024 15:12:13 UTC No. 16258211

>>16258199
>>16258200
Ranjeet, it even tells you explicitly to use the chain rule. What more hints do you need? If you want someone to write a full solution you'll have to offer some rupees as a reward.

Anonymous at Fri, 28 Jun 2024 15:16:56 UTC No. 16258216

>>16258199
This is a high school level math question that is dressed up with useless shit like galileo transformstion and relativity

Anonymous at Fri, 28 Jun 2024 15:24:00 UTC No. 16258231

>>16258202
>>16258211
>>16258216
>t. no solution

Anonymous at Fri, 28 Jun 2024 16:08:36 UTC No. 16258281

>>16258199
>>16258200
>homework thread

Anonymous at Fri, 28 Jun 2024 16:16:16 UTC No. 16258292

>>16258199
>>16258200
Dude just use Einstein's paper. He literally provides all the steps as this is literally what he did.

Anonymous at Fri, 28 Jun 2024 17:49:16 UTC No. 16258409

now do the same with air waves.

Anonymous at Fri, 28 Jun 2024 19:22:46 UTC No. 16258563

>>16258281
No, I'm preparing for a semester so I'm doing the challenge problems in university physics

Anonymous at Sat, 29 Jun 2024 03:05:57 UTC No. 16259205

>>16258199
>>16258200
>nu/sci/ thinks this is hard
/sci/ has fallen

Anonymous at Sat, 29 Jun 2024 08:27:14 UTC No. 16259478

[math] E(x+dx,t)-E(x,t) = E(x'+dx',t'+dt')-E(x,t) = E(x'+dx',t'+dt')-E(x',t'+dt')+E(x',t'+dt')-E(x,t) [/math]

[math] (E(x+dx,t)-E(x,t))/dx = dE(x,t)/dx = dE(x',t')*dx'/dx*(1/dx') + dE(x',t')*dt'/dx*(1/dt')' [/math]

x' = x - vt -> dx'/dx = 1 and dt'/dx = 0

[math] dE(x,t)/dx = dE(x',t')/dx' [/math]

Do the same for [math] (E(x+dx,t)-E(x,t))/dt, which results in dx'/dt = -v and dt'/dt = 1

[math] dE(x,t)/dt = dE(x',t')/dx' - v*dE(x',t')/dt' [/math]

You can repeat the above operation again to attain

[math] d^2E(x,t)/dt^2 = d^2E(x',t')/dt'^2 - 2v*d^2E(x',t')/dt'dx' + v^2*d^2E(x',t')/dx'^2 [/math]

[math] d^2E(x,t)/dx^2 = d^2E(x',t')/dx'^2 [/math]

Plug it all in to get:

[math] d^2E(x',t')/dx'^2-v^2/c^2*d^2E(x',t')/dx'^2+2v/c^2*d^2E(x',t')/dt'dx'-1/c^2 d^2E(x',t')/dt'^2 = 0 [/math]

Anonymous at Sat, 29 Jun 2024 08:40:08 UTC No. 16259482

>>16258199
>>16258200
Oh boy the schizos aren't gonna like this