Anonymous at Fri, 28 Jun 2024 15:21:53 UTC No. 16258225

>>16258219
Express cos(x) via Euler's identity in terms of exponentials. Integrating exponentials is trivial.

Anonymous at Fri, 28 Jun 2024 15:22:46 UTC No. 16258227

>>16258219
double partial integration.

Anonymous at Fri, 28 Jun 2024 16:20:32 UTC No. 16258295

>>16258219
Im(exp(1+i)x)

Anonymous at Sat, 29 Jun 2024 03:54:34 UTC No. 16259266

>>16258219
put it in a computer and get an answer as accurate as i want

Anonymous at Sat, 29 Jun 2024 04:20:40 UTC No. 16259299

>>16258219
You know how in integrals of cosx goes cosx, sinx, -cosx, etc. and how the derivatives of e^3x goes e^3x, 3e^3x, 9e^3x? Just integrate by parts twice, it's really basic.
You get S = [___] - 9S, which means S = 1/10[_____], which is the answer you got.

Anonymous at Sat, 29 Jun 2024 04:21:44 UTC No. 16259301

>>16259299
this is isn't an uncommon thing to see btw

Anonymous at Sat, 29 Jun 2024 06:28:29 UTC No. 16259375

>>16258219
This cannot be done. It would have to involve a Gaussian error function. Google Aquintology

Anonymous at Sat, 29 Jun 2024 07:16:07 UTC No. 16259428

e3x[ eix + e-ix]/2
->
e(3+i)x/(2{3+i})+e(3-i)x/(2{3-i})

Now work imaginary numbers out of denominator