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Anonymous at Sun, 8 Sep 2024 13:44:40 UTC No. 16368086
What is the physical meaning of Ricci curvature? I only ever saw it introduced with handwavy explanations like you want a symmetric tensor to make Einstein's equation work. But intuitively why would you contract Riemann curvature in this way and expect it to play part of a deep physical equation?
Anonymous at Sun, 8 Sep 2024 13:49:19 UTC No. 16368096
Keep your wits about you faggot I'm on my way, I'm doing everything by way of the best my mind can do.
Anonymous at Sun, 8 Sep 2024 21:23:20 UTC No. 16368719
No one knows differential geometry?
Anonymous at Mon, 9 Sep 2024 05:53:38 UTC No. 16369272
You should be asking about the scalar because that's what shows up in the action. But one explanation I've seen of the symmetric tensor is that it's related to the second derivative of the volume of a closed surface drawn through a bunch of freely falling bodies.