𧔠Untitled Thread
Anonymous at Mon, 14 Oct 2024 11:09:36 UTC No. 16430659
If the electron is orbiting the neutron in a hydrogren atom, then certainly it experiences acceleration. But accelerating charges emit photons. Where is the photon?
Anonymous at Mon, 14 Oct 2024 11:15:44 UTC No. 16430668
>>16430659
Is it 1912 again?
Why is it always 1912? I hate this stupid time machine.
Anonymous at Mon, 14 Oct 2024 11:19:37 UTC No. 16430674
>>16430668
Where is it?
Anonymous at Mon, 14 Oct 2024 11:21:54 UTC No. 16430677
>>16430659
>If the electron is orbiting the neutron
except it doesnât. And itâs the proton, not the neutron.
Anonymous at Mon, 14 Oct 2024 11:22:39 UTC No. 16430680
>>16430659
The electron doesn't orbit the proton. The electron's wavefunction stays stationary around the hydrogen nucleus. This is because the wavefunction has the form of [math]Ae^{-i \omega t}[/math] so when you multiply by the complex conjugate the result is [math]A^2[/math] and it doesn't depend on time
Anonymous at Mon, 14 Oct 2024 11:25:12 UTC No. 16430684
>>16430680
Uhu and how do you explain the electron being in different positions when I measure it 2 times with delay in-between if it doesnt move?
Anonymous at Mon, 14 Oct 2024 11:25:18 UTC No. 16430685
>>16430680
>This is because the wavefunction has the form of Ae^-iÏt
It doesnât. Itâs a bound state. The form you gave is for a free state (zero potential). And the wavefunction of that bound state isnât time-dependent.
Anonymous at Mon, 14 Oct 2024 11:26:58 UTC No. 16430691
>>16430684
You measurement localizes the wavefunction to these two points. Itâs not an instantaneous process. You can calculate the rate of decoherence if you want.
Anonymous at Mon, 14 Oct 2024 11:28:11 UTC No. 16430697
>>16430691
Uhu and if I localized in two different positions I have constraines the path of the electron to a line since there is no acceleration right?
Anonymous at Mon, 14 Oct 2024 11:33:46 UTC No. 16430707
>>16430697
There is âaccelerationâ (useless term in QM) since you interact with the system to measure it.
Anonymous at Mon, 14 Oct 2024 11:34:34 UTC No. 16430709
Idk, 4chan?
Anonymous at Mon, 14 Oct 2024 11:36:42 UTC No. 16430712
>>16430707
Aha so now you admit there IS acceleration. Then where is the photon?
Anonymous at Mon, 14 Oct 2024 11:37:43 UTC No. 16430714
>>16430712
Depends on how you measure the system. But at that point, it has nothing to do with the system in question which you had already disturbed.
Anonymous at Mon, 14 Oct 2024 11:40:00 UTC No. 16430723
>>16430714
It follows from your argunebt heisenberg's uncertainty principle has nothing to do with reality and everything to do with measurements
Anonymous at Mon, 14 Oct 2024 11:40:59 UTC No. 16430726
>>16430723
Maybe in your crackpot mind. I donât see how anything Iâve said relates to the uncertainty principle. Didnât even mention momentum once.
Anonymous at Mon, 14 Oct 2024 11:55:17 UTC No. 16430743
>>16430659
>Where is the photon?
Electron spins so fast it emits photon in counter phase and both photons cancel each other.
Anonymous at Mon, 14 Oct 2024 11:57:11 UTC No. 16430744
>>16430684
>>16430697
the electron can be in two places at the same time, that's why you can detect it in two different positions without having moved
Anonymous at Mon, 14 Oct 2024 13:25:56 UTC No. 16430855
>>16430712
nigga doesn't know about lasers and ion lamps
Anonymous at Mon, 14 Oct 2024 14:09:10 UTC No. 16430907
>>16430726
You said it depends on how I measure, obviously the electron has a momentum I can measure.
Anonymous at Mon, 14 Oct 2024 14:21:24 UTC No. 16430932
>>16430668
>>16430677
>>16430680
>>16430685
>>16430743
This is an important question. Letâs ignore the Bohr orbits, and state the electrons in stationary states have energies defined by the Schrödinger equation, in which, as Schrödinger originally wrote, the total energy is obtained from an entity Ï. What this means is that Ï has the properties of a wave, and hence a wavelength, and from de Broglie, the momentum, and thus the kinetic energy, is defined by that wave length. The electron cannot obey the Schrödinger equation and radiate electromagnetic radiation as required by Maxwellâs equations; the two cannot be completely obeyed at the same time. If you are only interested in an epistemic approach (shut up and calculate) there is no further problem - we know it follows the Schrödinger equation so, er, shut up and calculate.
If you want an ontological answer, that is, a physical reason for why this occurs, you wonât get one that everyone agrees with, and it is not easy to find one that is not even accepted. The one I offer is from my ebook âGuidance Wavesâ. This is a bit like the pilot wave, except I add the proposition that the physical wave only interacts with the particle (and vice versa) when, following Euler, the complex wave function becomes real, which is at the antinode, and when then action occurs as a discrete unit of h. In the stationary state, the electron only has physical constraints then, and if the antinode does not move, the state cannot change energy. It is whether the antinode accelerates, not the electron. You probably wonât agree with that. Most others do not because it requires the wave to be a physical entity.
Anonymous at Mon, 14 Oct 2024 14:35:26 UTC No. 16430960
>>16430907
Yes. And? That momentum doesnât change until you measure it. Youâre going
>gotcha, if I measure it, it emits light
and I say âso what?â You have already altered the state of the system from just the atom on its own to an external source interacting the atom.
Anonymous at Mon, 14 Oct 2024 14:37:59 UTC No. 16430963
>>16430932
Your entire longpost boils down to âI have never read about semiclassical EM or QEDâ. Every introductory grad-level QM book goes through it. See Sakurai for example.
Anonymous at Mon, 14 Oct 2024 14:49:01 UTC No. 16430990
>>16430963
nice try but this man has a phd
Anonymous at Mon, 14 Oct 2024 14:55:05 UTC No. 16431006
>>16430990
>le PhD
normalfags love appealing to authority. I witnessed PhD students fail to answer high school questions at their defenses. Knew a guy who couldnât name Standard Model coupings at his defense who is now a Princeton postdoc in an experimental group.
Anonymous at Mon, 14 Oct 2024 14:58:07 UTC No. 16431013
>>16431006
Yeah and u dont even have a phd so imagine how dumb u are
Anonymous at Mon, 14 Oct 2024 15:02:30 UTC No. 16431021
>>16431013
indeed
Anonymous at Mon, 14 Oct 2024 15:12:56 UTC No. 16431051
>>16430659
>But accelerating charges emit photons.
Does that mean there's a minimum acceleration?
Anonymous at Mon, 14 Oct 2024 17:14:22 UTC No. 16431374
>>16430659
Electrons don't have a position before being measured so they can't accelerate.
Anonymous at Mon, 14 Oct 2024 17:41:02 UTC No. 16431429
Looks like the answer has been stated in this thread
Anonymous at Mon, 14 Oct 2024 17:51:15 UTC No. 16431442
>>16431374
Does a proton have a position?
What about an elextron and a proton?
Does it have a position now?
What if I have a billion of them?
Anonymous at Mon, 14 Oct 2024 20:20:38 UTC No. 16431706
>>16431442
>Does a proton have a position?
Nope
>What about an elextron and a proton?
Nope
>Does it have a position now?
Nope
>What if I have a billion of them?
Nope
Anonymous at Mon, 14 Oct 2024 20:50:57 UTC No. 16431796
>>16431706
confirmed braindead