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🧵 What’s the function?

DumbOne No. 16446787

Pic unrelated
Is there a function for (24,12,8,6,4,3,2,1)?
This is a genuine question. I feel like there should be, but I honestly don’t know how to solve for it.

Anonymous No. 16446816

>>16446787
Yss you can make a polynomial function that passes by any arbritraty sets of points (as long as there aren't dupkicate y coordinates. Its called a lagrangian polynomial

Anonymous No. 16446822

>>16446816
The idea is simple, but im too tired to explain it so watch this video https://youtu.be/bzp_q7NDdd4?si=mknHUComLefIaN0G

Anonymous No. 16446841

f(n) = the nth factor of 24 in descending order

Anonymous No. 16446874

>>16446787
38.99999999995701 + (-4.702380952270616)x^1 + (-22.58055555566416)x^2 + (16.825000000054043)x^3 + (-5.347222222237147)x^4 + (0.8750000000023135)x^5 + (-0.07222222222241022)x^6 + (0.002380952380958602)x^7

f(1) = 23.999999999999996
f(2) = 11.999999999999615
f(3) = 7.999999999999545
f(4) = 5.999999999999574
f(5) = 3.99999999999892
f(6) = 2.9999999999995453
f(7) = 1.999999999998181
f(8) = 0.999999999998181

close enough, no?
>>16446787

Anonymous No. 16447133

>>16446787
f(n) = n^7/420 - 13n^6/180 + 7n^5/8 - 385n^4/72 + 673n^3/40 - 8129n^2/360 - 395n/84 + 39

there you go anooon

Anonymous No. 16447153

>>16446787
24/(d|24)

Anonymous No. 16447352

>>16446874
>close enough, no?
Boeing engineer?

DumbOne No. 16447359

>>16446816
>>16446822
>>16446841
>>16446874
>>16446874
>>16447133
>>16447153
Thanks chat. I really appreciate yall sharing your arcane secrets with me

Anonymous No. 16447417

>>16447352
kek

Anonymous No. 16447511

Set 1: 24 12 6 3

Set 2: 8 4 2 1

2 sets being multiplied by two

But the first set can only be multiples of the other times 3

3*2=6*2=12*2=24

1*3=3
2*3=6
4*3=12
8*3=24

16 is not included because 16/3=5.3 which isn't in the second set

Anonymous No. 16447713

>>16447511
>3*2=6*2=12*2=24
I messed that up but you know what I mean

Anonymous No. 16450230

>>16446787
sssyeah haha