Anonymous at Thu, 6 Feb 2025 21:00:23 UTC No. 16577795

>>16577776
>127
You need 128 to post here actually please leave

Socials, sharing and caring at Fri, 7 Feb 2025 08:55:47 UTC No. 16578249

>>16577795
>127

> OP used > sign wrong too iq is probably 27

Barkon !8v8vr3ErDk at Fri, 7 Feb 2025 09:06:17 UTC No. 16578258

>believes IQ works
>asks if midwit

Dude, you're not even a midwit, you're completely off the rails retarded.

XXXW

Anonymous at Fri, 7 Feb 2025 09:43:55 UTC No. 16578286

>>16578258
either retarded or 145 IQ

Anonymous at Fri, 7 Feb 2025 16:45:09 UTC No. 16578547

>>16577776
>AAABBCD
7 positions for D
6 positions for C
4+3+2 = 9 for the Bs
378 is the answer, I had an iq >130 as a child. I think I got dumber probably because of the drugs. I'm only like 30% confident this is the correct answer. I just counted where to put the letters and multiplied together... maybe the problem doesn't actually decompose that way I dunno.

Anonymous at Fri, 7 Feb 2025 16:48:11 UTC No. 16578549

>>16578547
>4+3+2 = 9 for the Bs
I missed the 2 B's at the end, should be 4+3+2+1
so answer is 420

Anonymous at Fri, 7 Feb 2025 16:56:22 UTC No. 16578557

>>16577776
Answer is 8!/(3!)(2!)

Anonymous at Fri, 7 Feb 2025 16:57:41 UTC No. 16578558

>>16578557
Correction - 7!/(3!)(2!)

Anonymous at Fri, 7 Feb 2025 17:06:48 UTC No. 16578567

I know how to do this kinda problem but this is a terrible interview question. The only reason to ask someone this is if you're looking for a reason not to hire them so you can hire some h1b jeets instead. Funny it humbled you enough to post here though lol.

Anonymous at Fri, 7 Feb 2025 17:41:24 UTC No. 16578594

>>16578286
Anon, that namefag is a well known retard.

Anonymous at Fri, 7 Feb 2025 17:46:25 UTC No. 16578600

>>16577776
Interviewers will evaluate everything you do, how you look, how you dress, how you speak, how you solve that problem. Even if you just say 420 you will be asked to describe in detail the steps you followed to reach that answer.

>>16578567
Retard take.

Anonymous at Sun, 9 Feb 2025 18:06:34 UTC No. 16580492

My answer: Without uniqueness the answer is 7!.
For every pattern, the three As can be switched in any order to produce 3! (=6) non unique patterns including itself.
Divide by 6 to get 7 * 5 * 4 * 3 * 2
Also the Bs can be switched to generate two non-uniques, so divide by two as well.
Final Answer: 7 * 5 * 4 * 3 = 420

Anonymous at Sun, 9 Feb 2025 18:12:12 UTC No. 16580496

>>16577776
I have a 118 IQ and this is trivial to me.

Anonymous at Tue, 11 Feb 2025 04:19:27 UTC No. 16582152

>>16577776
Do not start by trying to figure out how many positions does each letter have first, just think logically.
You have 7 letters, thus it should be 7!.
However, you have 2 instances of repetition, 2 B's and 3 A's.
So you must get rid of combinations taking account for the not unique letters. 3! for the As and 2! for the Bs.
7!/(2!)(3!)
420 (dude weed)

Anonymous at Thu, 13 Feb 2025 02:53:00 UTC No. 16584249

>>16577776
Do we only allow 7 letter codes? or [math]\leq 7[/math] letter codes as well?

Anonymous at Thu, 13 Feb 2025 02:55:36 UTC No. 16584250

>>16578558
I confirm this is the answer if it has to use all the letters.

Anonymous at Thu, 13 Feb 2025 03:12:08 UTC No. 16584263

>>16578549
For 2k an night they could be yours anon. Although they'd probably charge you more because you're not famous.

raphael at Thu, 13 Feb 2025 03:20:37 UTC No. 16584268

>>16577776
your iq isnt measured at 127

its prob high 90s

raphael at Thu, 13 Feb 2025 03:23:26 UTC No. 16584270

>>16578549
this is correct just factorial i think
im retarded

raphael at Thu, 13 Feb 2025 03:24:58 UTC No. 16584271

>>16584270
i was right

Anonymous at Thu, 13 Feb 2025 15:59:56 UTC No. 16584844

>>16577776
its easy: just get every possible combination and subtract the ones that are repeating:

you can start with any letter but ill start with "D" because i think you'll understand faster
I - "D" can be in 7 places and each will give a different combination each time, so thats 7 times the rest everything else

II - "C" can be in 7 places, except where "D" is, therefore thats 7-1=6 positions it can be and result in a different combintation each time, so thats 6 times the rest everything else

III - the first "B" you pick can be in 7 places, except where "D" or "C" will aready be, therefore thats 7-2=5 positions it can be and result in a different combintation each time, so thats 5 times everything else

IV - the second "B" you pick can be in 7 places, except where "D"," C" or the first "B" will aready be, therefore thats 7-3=4 positions it can be, but since swapping the first and the second "B" will not generate different combinations, we account for it by dividing the ammount of positions it can be placed by the number of repeating elements, which in this case amounts to 4/2, which equals 2 positions it can be {{{{{{{AND}}}}}}} result in a different combintation each time, so thats 2 times everything else

V - following the the explanation in "III" and "IV", each "A" can be in 7 positions, except where "D", "C", "B"s and other "A"s will be, therefore that's 7-4=3, and then 3/3=1, so thats 1 times everything else (the last element you account for is already implied to be in every other combination, which is why it always results in 1)

By "I", "II", "III", "IV", and "V" you get 7*6*5*2*1=420

Anonymous at Thu, 13 Feb 2025 16:00:57 UTC No. 16584848

>>16584844
if thats was too fast, you can also do like this:
V - following the the explanation in "III" for the first A: 7-4=3, 3 times everything else

VI - following the the explanation in "IV" for the the second A: 7-5=2, 2/2=1, 1 times everything else

VII - following the the explanation in "IV" for the the third A: 7-6=1, 1/3, 0.333... times everything else [notice that by "V", "VI" and "VII" amounts to 3*1*(1/3)=1, because the last element you account for is already implied to be in every other combination]
now that i think about it, i dont know how i would calculate if you didnt had to use all 7 slots

Anonymous at Thu, 13 Feb 2025 17:05:11 UTC No. 16584893

>>16578549
>>16578547
>I think I got dumber probably because of the drugs
>so answer is 420
you can't make this shit up

Anonymous at Thu, 13 Feb 2025 19:50:09 UTC No. 16585041

i got my wisdom teeth removed and my iq dropped from 115 to 111 :(

Anonymous at Thu, 13 Feb 2025 19:57:31 UTC No. 16585046

>>16585041
>your dentist

Anonymous at Fri, 14 Feb 2025 15:07:08 UTC No. 16585760

>>16577776
7*6*5*4/2! = 420 unique patterns
D C B B is the order of placements
IQ above 145, I almost got it wrong and yes I had that probability stuff in school. The division by 2! is because the order of B's doesnt matter.

Barkon !8v8vr3ErDk at Fri, 14 Feb 2025 15:12:42 UTC No. 16585765

IQ is a Governmental Student con where nerds profit socially from brandishing an ID that apparently represents their intelligence level, allowing them to skip any performance. It helps Jews. It helps fake news media shill propaganda over the TV. And most of all, Governmental Students get in bed with half witted males and females stupid fucking faggit.

Anonymous at Fri, 14 Feb 2025 15:23:15 UTC No. 16585773

>>16585760
To make it more complete
7*6*5*4/2!*3*2*1/3!
D C B B A A A
7*6*10*1
D C B A

Anonymous at Fri, 14 Feb 2025 15:35:07 UTC No. 16585783

>>16585765
Yea. Shits rough out there. 4chan is the only safe space left

Barkon !8v8vr3ErDk at Fri, 14 Feb 2025 15:41:43 UTC No. 16585787

>>16585783
Not even 4chan is safe, but there's fight here.

Barkon !8v8vr3ErDk at Fri, 14 Feb 2025 15:47:37 UTC No. 16585791

>>16585773
Me gusta

Anonymous at Fri, 14 Feb 2025 16:29:17 UTC No. 16585819

>>16585765
But you do admit that jews are smarter than you?