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๐Ÿงต Untitled Thread

Anonymous No. 16580989

What are some ways to solve this?

Anonymous No. 16581037

>>16580989
Show it as a recursive sequence
Verify the monotonicity and the boundedness of the sequence
Use the formula a = f(a) to get its fix point

Anonymous No. 16581082

>>16580989
Set y=2+bullshit
Add 1 to both sides of x=1+1/bullshit such that x+1=2+bullshit=y
substitute in y so x+1=2+1/y=y
multiply both sides of 2+1/y=y by y to get 2y+1=y^2
subtract 2y-1 from both sides so 2=y^2-2y+1
rewrite it as 2=(y-1)^2
take the square root so sqrt(2)=y-1
add 1 so sqrt(2)+1=y
substitute back y=x+1 so sqrt(2)+1=x+1
subtract 1 from both sides so x=sqrt(2)

Or save yourself a bunch of time and just look up the rule because anything that regular is definitely a rule.

Anonymous No. 16581093

>>16580989
Start typing it into the calculator. Observe the result with the extra terms added.
> It seems to converge to 1.4142...
The result is sqrt(2)

Anonymous No. 16581097

>>16580989
[eqn]
x + 1
= 2 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{\ddots}}}
= 2 + \frac{1}{x + 1}
\\
(x + 1)^2 = 2(x + 1) + 1 \Longrightarrow x^2 - 2 = 0
\\
x = \pm \sqrt 2
[/eqn]

Jesus christ, Hiroshimoot. 15 minutes and three captchas just to post this.

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Anonymous No. 16581105

>>16580989
x = Sqrt[2]
proof:
https://www.wolframalpha.com/input?i=1%2F%28x+-+1%29+%3D+1%2F%281%2F%28x+-+1%29+-+2%29

Anonymous No. 16581110

>>16580989
https://en.wikipedia.org/wiki/Simple_continued_fraction

Anonymous No. 16581119

>>16581093
>the calculator
the or a?

Sherlock Holmes No. 16581121

>>16581110
>https://en.wikipedia.org/wiki/Simple_continued_fraction
Oh, so you're using a stationary device, like a desktop, ay?
You should have replaced "en.wikipedia" with "en.m.wikipedia" in your URL.
Then we would have concluded, that you're using a mobile device, like a tablet.

good grief No. 16581124

>>16581097

omg he wrote: x^2 โ€“ 2 = 0
instead of: x^2 = 2

and then he wrote: x = +โ€“Sqrt[2]
even though: x > 0

Anonymous No. 16581132

>>16581119
The if it isnt a complex number

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Anonymous No. 16581230

the image depicts the continued fraction of: e โ€“ 1

Anonymous No. 16581238

>>16581230
>e โ€“ 1
"In a 1945 Popular Astronomy magazine article, the science writer D.E. Richardson apparently independently arrived at the same conclusion as Blagg: That the progression ratio is 1.728 rather than 2."

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Anonymous No. 16581918

https://www.wolframalpha.com/input?i=%7Bx+%2B+1+%3D+y%2C+1%2F%28y+-+2%29+%3D+y%7D