🧵 Untitled Thread
Anonymous at Thu, 20 Feb 2025 07:19:10 UTC No. 16592247
What is the equation of the curve? It passes through the points (9, 0), (10, –1) and (11, 0).
Anonymous at Thu, 20 Feb 2025 07:23:04 UTC No. 16592250
nigger
Anonymous at Thu, 20 Feb 2025 07:30:22 UTC No. 16592253
>>16592247
child, first tell us what your thought process is before we (against board rules) solve your middle school homework
Anonymous at Thu, 20 Feb 2025 07:37:51 UTC No. 16592258
Who are you calling a
>>16592250
>nigger
?
Anonymous at Thu, 20 Feb 2025 07:43:30 UTC No. 16592261
Who are you calling a
>>16592253
>child
?
>before we (against board rules) solve your middle school homework
it's not homework
thus no board rules are going to be violated
Anonymous at Thu, 20 Feb 2025 07:44:58 UTC No. 16592262
f(x)=a(x-9)(x-11)
Due factorization by zeros
now f(10)=a*(1)*(-1)=-1
So a is just 1
Thus f(x)=(x-9)(x-11)
bollyn dot com at Thu, 20 Feb 2025 07:54:08 UTC No. 16592276
>>16592262
>f(x)=(x-9)(x-11)
The curve almost passes through the points (8, 3) and (12, 3).
But your parabola passes through them.
Anonymous at Thu, 20 Feb 2025 07:55:58 UTC No. 16592277
>>16592276
If it aint parabola then you call this the best polynomial approximation and call it a day
Anonymous at Thu, 20 Feb 2025 08:04:11 UTC No. 16592282
What are you calling
>>16592277
>a day
?
Anonymous at Thu, 20 Feb 2025 19:08:12 UTC No. 16593505
another hint:
a + b*y = cos(x*pi/10)
Anonymous at Thu, 20 Feb 2025 19:35:16 UTC No. 16593594
>>16592294
>>16593505
But that's wrong. The correct solution is
https://www.desmos.com/calculator/r
Anonymous at Fri, 21 Feb 2025 01:18:59 UTC No. 16594254
>>16593594
>But that's wrong.
no, it ain't
i know, because i have the solution
>The correct solution is
>https://www.[...]
omg, like i'm really gonna go to that website
plus how can the solution be encoded in the suffix of your URL?
Anonymous at Fri, 21 Feb 2025 06:42:37 UTC No. 16594493
>>16592247
Technically, you haven't given us enough information to give unique answer. I'm guessing it's implied that this is a quadratic curve, in which case:
>>16592262
is correct. But if it's only guaranteed to be an arbitrary polynomial, then you can use a method called lagrangian interpolants to create an infinite number of distinct solutions that pass through these 3 points.
Anonymous at Fri, 21 Feb 2025 10:53:20 UTC No. 16594648
>>16592282
Workday is over and you go home from math job
Anonymous at Fri, 21 Feb 2025 11:04:23 UTC No. 16594654
>>16592262
>Not using the derivative
Nigger
Anonymous at Fri, 21 Feb 2025 11:45:25 UTC No. 16594682
1st hint: cosine
2nd hint: a + b*y = cos(x*pi/10)
3rd hint: find the variable a first
Anonymous at Fri, 21 Feb 2025 11:47:27 UTC No. 16594686
>>16594493
/thread
low IQ retards on this board think every curve is a parabola
OP at Fri, 21 Feb 2025 12:15:43 UTC No. 16594706
>>16594493
>Technically, [the 1st post has]n't given us enough information to give [a] unique answer.
True.
But that's no longer the case, considering the information in the 11th post ( >>16593505 ).
>I'm guessing it's implied that this is a quadratic curve, in which case: [the 6th post] is correct.
The 7th post ( >>16592276 ) says, that it isn't a quadratic curve!