🧵 Untitled Thread
Anonymous at Fri, 4 Apr 2025 01:34:57 UTC No. 16636913
so given a box of X, Y, and Z dimensions, what would actually be the minimum of
[math]\sqrt{a^2+y^2}+\sqrt{(x-a)^2+
Anonymous at Fri, 4 Apr 2025 01:57:48 UTC No. 16636920
[math]a=(z*x)/(z+y)[/math]
Anonymous at Fri, 4 Apr 2025 02:00:54 UTC No. 16636922
>hint: it's not B
>no, we didn't tell you there is an open side
>we also didn't tell you where the opening is
>have fun making shit up, retard
Nice disingenuous prompt.
Anonymous at Fri, 4 Apr 2025 10:28:35 UTC No. 16637144
>>16636913
I unlock the 4th dimension and put one morsel at times in the future immediately before the bug starves
Anonymous at Fri, 4 Apr 2025 11:13:22 UTC No. 16637168
My intuition is this: the bug will always try to minimize distance traveled by taking diagonal paths. So to maximize its distance, force one of its paths to be along the edge instead of diagonal. You want it to traverse the longest edge, so put it directly above A. Maximize distance traveled is then 2 + rt(2).